Yes, I agree with you.ecoo said:Homework Statement
I reference the problem posted here: https://www.physicsforums.com/threads/work-and-spring-problem.194531/
Homework Equations
Work = Force * Distance
F = kx
The Attempt at a Solution
Wouldn't the limits of integration in part 2 be from 5 to 9, since x is the compression distance, not the length of the spring?
Thanks!
The work done on a spring is the amount of energy required to stretch or compress it from its initial position to a new position. This work is typically measured in joules (J) and is equal to the force applied to the spring multiplied by the distance it is stretched or compressed.
The work done on a spring can be calculated using the formula W = 1/2kx², where W is the work done, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
The work done on a spring is equal to the change in potential energy of the spring. This means that when work is done on a spring, its potential energy increases or decreases depending on whether it is being stretched or compressed.
No, work cannot be done on a spring without changing its potential energy. This is because the work done is directly related to the change in potential energy of the spring.
The work done on a spring is directly proportional to the spring constant. This means that as the spring constant increases, the amount of work required to stretch or compress the spring also increases.