May 12, 2021 Thread starter #1 N Nousher New member May 11, 2021 7 We can rewrite |x-3|<10 in the following way. -10<x-3<10 But can rewrite |x-3|+|x+1|+|x|<10 in the following way? -10<x-3+x+1+x<10. If we cannot, will anybody please explain why we cannot?

We can rewrite |x-3|<10 in the following way. -10<x-3<10 But can rewrite |x-3|+|x+1|+|x|<10 in the following way? -10<x-3+x+1+x<10. If we cannot, will anybody please explain why we cannot?

Jun 6, 2021 #2 R romsek New member Mar 27, 2017 3 You can't write it that way because it's not in general correct. You can write it as a union of such rules though. In this case it appears to be $(x < -\dfrac 8 3) \cup (4 < x)$

You can't write it that way because it's not in general correct. You can write it as a union of such rules though. In this case it appears to be $(x < -\dfrac 8 3) \cup (4 < x)$