- #1
Unit
- 182
- 0
How is this possible?
[tex]\int_{i\infty}^\pi e^{ix} dx = i[/tex]
I mean, I understand that the integral of exp(ix) is -i exp(ix) and then you evaluate that from π to i∞ — but that's exactly it, how does one "draw a line" from (π, 0) on the Argand plane to (0, ∞)? (assuming Argand plane tuples (a, b) ↔ a + bi)
EDIT: fixed the integrand, thanks Mute
[tex]\int_{i\infty}^\pi e^{ix} dx = i[/tex]
I mean, I understand that the integral of exp(ix) is -i exp(ix) and then you evaluate that from π to i∞ — but that's exactly it, how does one "draw a line" from (π, 0) on the Argand plane to (0, ∞)? (assuming Argand plane tuples (a, b) ↔ a + bi)
EDIT: fixed the integrand, thanks Mute
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