- #1
Rectifier
Gold Member
- 313
- 4
The problem
I want to solve ##tan(a)=-1## where a is in degrees.
The attempt
## tan(a)= \frac{sin(a)}{cos(a)}=-1 \ \ cos(a) \neq 0 \\ \frac{sin(a)}{cos(a)}=-1 \\ sin(a)=-cos(a) \\ -sin(a)=cos(a) \\ sin(-a)=cos(a) ##
I have no idea how to continue from here.
I want to solve ##tan(a)=-1## where a is in degrees.
The attempt
## tan(a)= \frac{sin(a)}{cos(a)}=-1 \ \ cos(a) \neq 0 \\ \frac{sin(a)}{cos(a)}=-1 \\ sin(a)=-cos(a) \\ -sin(a)=cos(a) \\ sin(-a)=cos(a) ##
I have no idea how to continue from here.