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kraigandrews
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kraigandrews said:I'm trying to find r(theta)
kraigandrews said:then second part of my question i have to do is find the coordinates where r(theta) crosses the y-axis however, where i run into the problem is the integral i found doesnot cross the y-axis
Horizontal escape of a projectile, also known as horizontal range, is the maximum distance a projectile travels horizontally before returning to the ground.
The horizontal escape of a projectile is affected by the initial velocity, angle of launch, air resistance, and gravitational pull of the Earth.
The horizontal escape of a projectile can be calculated using the formula: R = (v^2 * sin(2θ))/g, where R is the horizontal range, v is the initial velocity, θ is the angle of launch, and g is the gravitational acceleration.
The optimal angle of launch for maximum horizontal escape is 45 degrees, as it allows for the greatest distance to be covered while minimizing the effects of air resistance.
The horizontal escape of a projectile refers to the distance traveled horizontally, while the vertical escape refers to the maximum height reached by the projectile. These two values are independent of each other and can be calculated separately.