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A heat engine has an efficiency of 25.0% and its heat input is 600J per cycle from the high-temperature reservoir. What is the rate of heat output to the low-temperature reservoir per cycle?
E=(Qh-Qc)/Qh
.25=(600J-Qc)/600J
Qc=450J
book has the answer as 800J.
How are they getting 800J and not 450J?
E=(Qh-Qc)/Qh
.25=(600J-Qc)/600J
Qc=450J
book has the answer as 800J.
How are they getting 800J and not 450J?