JR9 said:Homework Statement
4 charges of +5µC, +3µC, -4µC and +2µC form the 4 points of a square of side length 2m. Calculate the field strength and potential at the centre of the square.
Homework Equations
F=1/4π[PLAIN]http://upload.wikimedia.org/math/d/3/c/d3c305fc416b971cd6d284564e51bf85.png[SUB]0[/SUB] X Q1Q2/r2
E= Q/4π[PLAIN]http://upload.wikimedia.org/math/d/3/c/d3c305fc416b971cd6d284564e51bf85.png[SUB]0[/SUB] r2
The Attempt at a Solution
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The formula for calculating electric field strength at the center of a square is E = Q/(4πεr²), where E is the electric field strength, Q is the charge, ε is the permittivity of the medium, and r is the distance from the center of the square.
To determine the direction of the electric field at the center of a square, you need to consider the direction of the individual electric fields from each charge present in the square. If the charges are positive, the direction of the electric field will be away from them. If the charges are negative, the direction of the electric field will be towards them. The overall direction of the electric field at the center of the square will be the vector sum of these individual electric fields.
The unit of measurement for electric field strength is volts per meter (V/m).
Yes, it is possible for the electric field strength at the center of a square to be zero. This can occur when the charges in the square are arranged in such a way that their individual electric fields cancel each other out.
The electric field strength at the center of a square is inversely proportional to the square of the distance from the center. This means that as the distance increases, the electric field strength decreases, and vice versa.