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#### Linus12351

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- Mar 26, 2020

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- Thread starter Linus12351
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- Mar 26, 2020

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Have you tried looking at \(\displaystyle \lim_{n \to \infty} \dfrac{a_{n + 1}}{a_n}\)?Can anyone help with this problem. I've tried integral test but seems to be too complicated.

-Dan

Easy,Can anyone help with this problem. I've tried integral test but seems to be too complicated.

$\displaystyle 0 \leq \sum{\frac{1}{5^{n-1} + 1}} < \sum{\frac{1}{5^{n-1}}} = \sum{ \left( \frac{1}{5} \right) ^{n-1} }$

Since your positive term series is less than a convergent geometric series, your series converges by comparison.