Help With Lift And Drag Forces On A Ball, Bernoullis Principles.

In summary: N C2: F=(1/2)Pv^2CA = (.5 x 1.225 x 7.2^2 x 424 x 1)=4,911 NIn summary, we are asked to calculate the lift and drag forces exerted on a ball in different vertical and inclined levitation scenarios. Using the formula F=(1/2)Pv^2CA, we can calculate the lift force for each scenario by plugging in the given values for density, velocity, and cross section. We can also calculate the drag force using the formula CD=2FD/PV^2A, where CD is the drag coefficient. We use a
  • #1
imamul
2
0

Homework Statement


Any help would be appreciated, whether that is formulas or working out.
Questions
For each of the vertical levitation examples calculate the lift force exerted on the ball.

For each of the inclined levitation examples calculate the lift and drag forces exerted on the ball.

BeachBall, Circumference = 73cm, Weight = 100g

Velocities At Different Points On The BeachBall at 90 degrees, From Far Left To Far Right:
A1: 0.5 m/s
B1: 5 m/s
C1: 13.5 m/s
D (center): 15.5 m/s
A2: 0.4 m/s
B2: 5.1 m/s
C2: 10.5 m/s

Velocities At Different Points On The BeachBall at 45 degrees, From Far Left To Far Right:
A1: 0.1 m/s
B1: 2.2 m/s
C1: 7.6 m/s
D (center): 11.2 m/s
A2: 0 m/s
B2: 2.5 m/s
C2: 7.2 m/s

Homework Equations


Dont know, have attempted to find.

The Attempt at a Solution


Formula used:
F=(1/2)Pv^2CA
P=density
A=cross section
v=velocity
c=drag coefficient

CD=2FD/PV^2A

CD=2FD/110 x 11.2^2 x424

A= Pi r^2
Diameter = 23.23
R= 11.615
 
Last edited:
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  • #2
A= 424Vertical LevitationA1: F=(1/2)Pv^2CA = (.5 x 1.225 x 0.5^2 x 424 x 1)=106.5 N B1: F=(1/2)Pv^2CA = (.5 x 1.225 x 5^2 x 424 x 1)=3,637 N C1: F=(1/2)Pv^2CA = (.5 x 1.225 x 13.5^2 x 424 x 1)=20,343 N D (center): F=(1/2)Pv^2CA = (.5 x 1.225 x 15.5^2 x 424 x 1)= 24,561 N A2: F=(1/2)Pv^2CA = (.5 x 1.225 x 0.4^2 x 424 x 1)=51.04 N B2: F=(1/2)Pv^2CA = (.5 x 1.225 x 5.1^2 x 424 x 1)=3,892 N C2: F=(1/2)Pv^2CA = (.5 x 1.225 x 10.5^2 x 424 x 1)=14,955 N Inclined LevitationA1: F=(1/2)Pv^2CA = (.5 x 1.225 x 0.1^2 x 424 x 1)=10.2 N B1: F=(1/2)Pv^2CA = (.5 x 1.225 x 2.2^2 x 424 x 1)=472.7 N C1: F=(1/2)Pv^2CA = (.5 x 1.225 x 7.6^2 x 424 x 1)=6,858 N D (center): F=(1/2)Pv^2CA = (.5 x 1.225 x 11.2^2 x 424 x 1)=9,959 N A2: F=(1/2)Pv^2CA = (.5 x 1.225 x 0^2 x 424 x 1)=0 N B2: F=(1/2)Pv^2CA = (.5 x 1.225 x 2.5
 

Related to Help With Lift And Drag Forces On A Ball, Bernoullis Principles.

1. What are lift and drag forces?

Lift and drag forces are two aerodynamic forces that act on an object as it moves through a fluid, such as air. Lift is the force that acts perpendicular to the direction of motion and is responsible for keeping an object airborne. Drag is the force that acts parallel to the direction of motion and opposes the object's motion.

2. How do lift and drag forces affect a ball?

Lift and drag forces play a significant role in the flight of a ball. As the ball moves through the air, lift force is generated due to the difference in air pressure above and below the ball. This lift force allows the ball to stay in the air and can be manipulated by changing the shape or spin of the ball. Drag force, on the other hand, acts in the opposite direction of the ball's motion and can slow it down.

3. What is Bernoulli's principle?

Bernoulli's principle states that as the speed of a fluid (such as air) increases, its pressure decreases. This principle is important in understanding lift force, as the faster moving air above the ball creates a lower pressure, resulting in a pressure difference that generates lift.

4. How does spin affect lift and drag forces on a ball?

Spin can have a significant impact on the lift and drag forces acting on a ball. For example, a spinning ball will experience a Magnus force, which is a sideways force that can cause the ball to curve in flight. Additionally, the spin can also affect the airflow around the ball, altering the amount of lift and drag forces generated.

5. Can lift and drag forces be controlled?

Yes, lift and drag forces can be controlled by manipulating the shape, size, and surface properties of an object. For example, the dimples on a golf ball are designed to reduce drag and increase lift, allowing the ball to travel farther. The angle of attack, or the angle at which an object meets the fluid, can also be adjusted to control the lift and drag forces acting on it.

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