Help with Images and Optical Instrument Question

[Jfhebb]

An object is placed two focal lengths from a diverging lens, (a) What kind of image forms? (b) What is the magnification? (c) Where is the image?

I am pretty sure the image is virtual, as for (b) and (c) I have no idea what to do.. Looking for some help, thanks in advance..


(a) I am pretty sure it is virtual
I am not sure what to do for b or c, I know we are looking for the Si for c, and as far as b goes I am not sure what magnification formula to use as we are given no values.
(b)
(c)
Thanks in advance,

 

[rl.bhat]

The object distance do is 2f, focal length is f. Find the image distance di using relevant equation. It should be less than f. Magnification = di/do

 

[kerimek]

Hello! I can help you with your questions regarding images and optical instruments.

(a) Based on the information provided, the image formed by a diverging lens when an object is placed two focal lengths away is indeed a virtual image. This means that the light rays do not actually converge at the location of the image, but they only appear to come from that point when viewed from the other side of the lens.

(b) In order to calculate the magnification, we need to know the distance between the object and the lens (u) and the distance between the image and the lens (v). However, since we are not given any values, we cannot calculate the magnification.

(c) Similarly, without knowing the distances between the object and the lens and between the image and the lens, we cannot determine the exact location of the image. However, we do know that the image will be located on the opposite side of the lens from the object, and it will be virtual.

I hope this helps! If you have any further questions, please don't hesitate to ask.