- #1
nearc
Gold Member
- 66
- 6
this starts as a calculus question, but springs into where i can get help with david bachman's A GEOMETRIC APPROACH TO DIFFERENTIAL FORMS second edition.
looking at paul's notes cheat sheets http://tutorial.math.lamar.edu/cheat_table.aspx we have##
\int \frac{1}{\sqrt{a^{2}-x^{2}}} = sin^{-1}(\frac{x}{a})+c
##
but this is different than wolfram http://www.wolframalpha.com/input/?i=integral&a=*C.integral-_*Calculator.dflt-&f2=1/sqrt(a^2-x^2)&f=Integral.integrand_1/sqrt(a^2-x^2)&a=*FVarOpt.1-_**-.***Integral.rangestart-.*Integral.rangeend--.**Integral.variable---.*--
however, all i really want to know is this correct?
## \int \frac{1}{\sqrt{1-a^{2}-x^{2}}} = sin^{-1}(\frac{x}{\sqrt{1-a^{2}}})+c ##
looking at paul's notes cheat sheets http://tutorial.math.lamar.edu/cheat_table.aspx we have##
\int \frac{1}{\sqrt{a^{2}-x^{2}}} = sin^{-1}(\frac{x}{a})+c
##
but this is different than wolfram http://www.wolframalpha.com/input/?i=integral&a=*C.integral-_*Calculator.dflt-&f2=1/sqrt(a^2-x^2)&f=Integral.integrand_1/sqrt(a^2-x^2)&a=*FVarOpt.1-_**-.***Integral.rangestart-.*Integral.rangeend--.**Integral.variable---.*--
however, all i really want to know is this correct?
## \int \frac{1}{\sqrt{1-a^{2}-x^{2}}} = sin^{-1}(\frac{x}{\sqrt{1-a^{2}}})+c ##
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