Help with a velocity and accleration problem

In summary, the car's velocity being in the direction of the truck is not necessarily true, and it can have a negative velocity even when going faster. For the second problem, using the kinematic equations, the length of the barrel can be calculated given the final velocity, acceleration, and time it takes for the bullet to accelerate. The length of the barrel is about 2.8 feet.
  • #1
nando94
33
0
1. An 18 wheeler and a sports car in adjacent lanes at any given moment. If the car's speed is faster than the trucks speed, which of the following must be true about the car's velocity...

a) its increasing
b) its in the direction of the truck
c) its zero
d) none of the above

I said it was d because the truck and car are side by side. Even though the car is going faster, it can have a negative velocity which means the driver is pushing the brake pedal to stay in line with the truck. So I was thinking the velocity was decreasing but I am confused if its right or not.

2. A bullet takes 8 milliseconds to accelerate the entire length of the gun barrel. When the bullet leaves the barrel, it has a velocity of 240 m/s. Assuming that the bullet has a uniform acceleration, what is the length of the barrel?


I was really lost with this one. I know final velocity is 240 and beyond that I am confused.
 
Physics news on Phys.org
  • #2
#2.
These equations apply for objects with constant acceleration. Maybe give it a try with these and repost with work if you still can't get it.

[tex] v = v_0 + a t [/tex]
[tex] x = x_0 + v_0 t + (1/2) a t^2 [/tex]
 
  • #3
nando94 said:
1. An 18 wheeler and a sports car in adjacent lanes at any given moment. If the car's speed is faster than the trucks speed, which of the following must be true about the car's velocity...

a) its increasing
b) its in the direction of the truck
c) its zero
d) none of the above

I said it was d because the truck and car are side by side. Even though the car is going faster, it can have a negative velocity which means the driver is pushing the brake pedal to stay in line with the truck. So I was thinking the velocity was decreasing but I am confused if its right or not.
I think you misread the problem. It does not say that the car and truck are side by side; it just says that they are in adjacent lanes, and that he car has a greater speed. Rethink the explanation of your chosen answer.
2. A bullet takes 8 milliseconds to accelerate the entire length of the gun barrel. When the bullet leaves the barrel, it has a velocity of 240 m/s. Assuming that the bullet has a uniform acceleration, what is the length of the barrel?


I was really lost with this one. I know final velocity is 240 and beyond that I am confused.
You know the final velocity as it leaves the barrel. It's initial speed at the beginning of the barrel is how much? Use one of the kinematic equations to solve for the barrel length.
 
  • #4
DukeLuke said:
#2.
These equations apply for objects with constant acceleration. Maybe give it a try with these and repost with work if you still can't get it.

[tex] v = v_0 + a t [/tex]
[tex] x = x_0 + v_0 t + (1/2) a t^2 [/tex]

A bullet takes 8 milliseconds to accelerate the entire length of the gun barrel.

Thats the part I am most confused about. Is that time or acceleration? I am assuming that its time causing its saying it takes .008 seconds to acclerate the entire length.
 
  • #5
PhanthomJay said:
I think you misread the problem. It does not say that the car and truck are side by side; it just says that they are in adjacent lanes, and that he car has a greater speed.

So does that mean that the car's velocity is in the direction of the truck.

But what if the car and truck were neck and neck but the car had a greater speed. Does that mean that the car has a negative velocity?
 
  • #6
nando94 said:
So does that mean that the car's velocity is in the direction of the truck.
the question says nothing initially about velocity. It makes reference to speed, which has no direction associated with it (speed is a scalar quantity).
But what if the car and truck were neck and neck but the car had a greater speed. Does that mean that the car has a negative velocity?
The car could be traveling neck and neck , ahead of, or behind, the truck, at any given moment, in the same or opposite direction. So which is the correct answer, and why?
 
  • #7
PhanthomJay said:
the question says nothing initially about velocity. It makes reference to speed, which has no direction associated with it (speed is a scalar quantity). The car could be traveling neck and neck , ahead of, or behind, the truck, at any given moment, in the same or opposite direction. So which is the correct answer, and why?

Oh so its zero right since it doesn't have a vector.
 
  • #8
DukeLuke said:
#2.
These equations apply for objects with constant acceleration. Maybe give it a try with these and repost with work if you still can't get it.

[tex] v = v_0 + a t [/tex]
[tex] x = x_0 + v_0 t + (1/2) a t^2 [/tex]

oaky so I did 240 m/s = 0 m/s + a(.008s)

a = 30,000 m/s^2

then

x = 0 + 0 + (1/2) 30,000m/s^2 (.008s)^2

x = .86m

or about 2.8 feet

but a guna that is 2.8 feet? I think I did something wrong. Is the initial velocity zero because that's what I assumed?
 
  • #9
That looks right, except you should check your answer for the length because your equation is right and your answer is slightly off. This is a bit long for a barrel, but not ridiculous for a rifle -you can't always assume the problem is well written either :). It's good that you think about if your answer makes sense though.
 

Related to Help with a velocity and accleration problem

What is velocity and acceleration?

Velocity is the rate of change of an object's position over time. It is a vector quantity, meaning it has both magnitude and direction. Acceleration is the rate of change of an object's velocity over time.

How do you calculate velocity?

Velocity can be calculated by dividing the change in position (Δx) by the change in time (Δt). This can be represented by the equation v = Δx/Δt. Velocity is usually measured in meters per second (m/s).

How do you calculate acceleration?

Acceleration can be calculated by dividing the change in velocity (Δv) by the change in time (Δt). This can be represented by the equation a = Δv/Δt. Acceleration is usually measured in meters per second squared (m/s²).

What is the difference between velocity and speed?

Velocity and speed are often used interchangeably, but they are not the same. While velocity is a vector quantity that includes both magnitude and direction, speed is a scalar quantity that only measures magnitude. This means that velocity can change even if an object is moving at a constant speed, as long as the direction of motion changes.

How do you use velocity and acceleration in a problem?

Velocity and acceleration can be used to solve a variety of problems, such as calculating the distance an object travels, the time it takes to reach a certain speed, or the force needed to change its velocity. It is important to identify the known and unknown variables, and then use the appropriate equations to solve for the unknown quantity.

Similar threads

  • Introductory Physics Homework Help
Replies
6
Views
805
  • Introductory Physics Homework Help
Replies
9
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
2
Views
5K
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
4K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
3K
Back
Top