Absolutely, I have tried to break up the right side of the equation, so that the equation looks like: 2x/7= (2x)(2x)When our members post questions, we expect for them to show what they have tried, or what they think they should do, or at the very least state that they simply have no idea how to begin. This way our helpers no where the person is stuck and can offer guidance at that point.
Can you show what you have tried and where you are stuck?
Starting from the beginning or where I currently have the equation?The first thing I would do is observe that both sides have 2 as a factor, so I would divide through by 2. What does your equation look like now?
Alright, maybe I figured it out. I got x=7. Let me explain:I'm sorry, from the beginning:
[JUSTIFY]And for the record, this approach is essentially correct (with MarkFL's warning that dividing by zero implies that x is not zero, so you need to take that into account and check whether zero is in fact a solution, this often confuses students and so is not generally taught until later) but you made a mistake in your computation (in red), leading you to a wrong solution. Can you see the error?[/JUSTIFY]Alright, maybe I figured it out. I got x=7. Let me explain:
Divide each side by two
Divide each side by x
Simplify to: (mistake going from above to below)
I'm a bit confused on when you can cancel while dividing. Is it just when the top & bottom mach because they would just equal one?