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- Jan 29, 2012

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As MarkFL pointed out, you can have f(0)= 16 or -3 but not both.f(x) = {

{ 16 - x^2, if -4 <= x <= 0

{ 2x - 3, if 0 <= x <= 4

I did the first derivative test and got zero but i dont think thats right. Any help?

The derivative of [tex]16- x^2[/tex] is -2x which is 0 at x= 0 which is a "break point". Of course, the derivative of 2x- 3 is never 0.

That tells you that a local minimum must occur at x= -4, x= 0, or x= 4. Without knowing if f(0) is 16 or -3, we cannot say which or even if f