HELP - Calculus: Related Rates

In summary, the person is asking for help with a math problem, and is not sure how to proceed. They mention that they have done some work on the problem, but are not sure how to solve it.
  • #1
p4nda
16
0
Hi, I have no clue on how to work these problems out. Due tomorrow, please help! Thanks.

http://img.photobucket.com/albums/v299/p4nda/RelatedRates.jpg
 
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  • #2
The first step is to always identify and write down the given variables mathematically.
For question 14, you can draw a right-triangle with Inge at the ground vertex, and the kite at the top vertex. The string is the hypotenuse, so the height of the kite above the ground is the vertical leg which is 300ft. The length of the horizontal leg is variable with time, we'll call it x. We are given dx/dt = 25 ft/s. We want to find ds/dt when x=500ft, where s is the length of the string. We note that ds/dt = (ds/dx)(dx/dt) by the chain rule. Thus, if we write a function s = s(x) and differentiate it at x = 500ft, we will have the missing rate in our equation. Can you find an equation relating s and x ?
 
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  • #3
A little late, eh? Have you done any work on these? We're here to help you learn how to solve problems, not give you answers.

P.S. please don't spam.
 
  • #4
hypermorphism said:
The first step is to always identify and write down the given variables mathematically.
For question 14, you can draw a right-triangle with Inge at the ground vertex, and the kite at the top vertex. The string is the hypotenuse, so the height of the kite above the ground is the vertical leg which is 300ft. The length of the horizontal leg is variable with time, we'll call it x. We are given dx/dt = 25 ft/s. We want to find ds/dt when x=500ft, where s is the length of the string. We note that ds/dt = (ds/dx)(dx/dt) by the chain rule. Thus, if we write a function s = s(x) and differentiate it at x = 500ft, we will have the missing rate in our equation. Can you find an equation relating s and x ?

Thanks! :smile:
 
  • #5
Hurkyl said:
A little late, eh? Have you done any work on these? We're here to help you learn how to solve problems, not give you answers.

P.S. please don't spam.

Haha, yeah... a little late. But I've done some work on these.

P.S. Sorry. =/
 

Related to HELP - Calculus: Related Rates

1. What is related rates in calculus?

Related rates in calculus is a branch of mathematics that deals with finding the rate of change of one variable with respect to another variable that is also changing. It involves using the chain rule and implicit differentiation to solve problems involving rates of change in real-world scenarios.

2. What are some real-world applications of related rates?

Related rates can be applied in various fields such as physics, engineering, economics, and medicine. Some examples include finding the rate at which the volume of a balloon is changing as it is being inflated, determining the speed of an object based on its position and time, and calculating the rate of change of drug concentration in a patient's bloodstream.

3. How do you set up a related rates problem?

To set up a related rates problem, you first need to identify the variables and their rates of change. Then, you need to write an equation that relates the variables together. Next, take the derivative of the equation with respect to time and substitute in the given rates of change. Finally, solve for the desired rate of change by isolating the variable and plugging in the known values.

4. What is the chain rule and how is it used in related rates?

The chain rule is a calculus rule that allows us to find the derivative of a composite function. In related rates, it is used to find the derivative of an equation with respect to time, where the variables are dependent on each other. This allows us to find the rate of change of one variable in terms of the rate of change of another variable.

5. What are some common mistakes to avoid when solving related rates problems?

Some common mistakes to avoid when solving related rates problems include not clearly identifying the variables and their rates of change, using the wrong formula or equation, and not properly differentiating the equation with respect to time. It is also important to carefully read the problem and make sure all given information is accounted for in the equation.

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