A race car traveling at +44 m/s

[Integral0]

A race car traveling at +44 m/s is uniformly accelerated to a velocity of +22 m/s over an 11-s interval. What is the displacement during this time?

(Don't solve it)

Why is the car being accelerated from +44 m/s to +22 m/s . . . wouldn't it be deacceleration?

 

[Integral0]

figured it out

heh, deacceleration is acceleration just in the opposite direction; therefore, deacceleration can be positive or negative.

Thanks Royhaas!

 

[M98Ranger]

The car is being uniformly accelerated from +44 m/s to +22 m/s, meaning that the acceleration is constant and in the same direction as the initial velocity. This can happen if the car is slowing down, but at a constant rate. So, the car is still accelerating, just in the opposite direction of its initial velocity.