Radioactive decay in relativistic frames

In summary: Therefore, the object would appear to slow down as if it were approaching the event horizon but would never actually fall in.
  • #1
Tyro
105
0
If you take two identical radioactive samples, place one on Earth and another on a near-lightspeed spaceship, and compare them some time later, will the one left on Earth have undergone comparatively more radioactive decay than the one on the spaceship?

If the experiment is repeated by leaving one on Earth and another on a planet with the same radius as Earth but made entirely of lead, what, if any, will the difference be?

Finally, how would the radioactive decay of a test source on the surface of Earth and its centre compare?
 
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  • #2
Originally posted by Tyro
If you take two identical radioactive samples, place one on Earth and another on a near-lightspeed spaceship, and compare them some time later, will the one left on Earth have undergone comparatively more radioactive decay than the one on the spaceship?

Yes. (assuming that the second sample is brought back to a state where it is motioness wrt the first when the comparision is made. )


If the experiment is repeated by leaving one on Earth and another on a planet with the same radius as Earth but made entirely of lead, what, if any, will the difference be?

The sample sitting on Earth will decay faster.


Finally, how would the radioactive decay of a test source on the surface of Earth and its centre compare?

The sample on the surface will decay faster.
 
  • #3
This relativistic effect on decay time has been obseved. Muons produced from cosmic rays come to Earth at speeds close to c. As a result they live longer than expected.
 
  • #4
Does that mean that time dilation slows time down to a near standstill as you near the centre of a black hole, but the second (excuse the pun) you hit the centre, time goes discontinuously back to normal?

Or is it generally accepted that some kind of bridging theory must be made between physics as we know it and the physics at a singularity, thus making the above interpretation speculative?
 
  • #5
An outside observer sees something falling into a black hole slow down and never fall in. In fact, to the outside observer, the black hole never formed.

On the other hand, an object falling in would be in a different reference frame and would simply pass the event horizon and quickly be destroyed.
 

What is radioactive decay?

Radioactive decay is the process by which unstable atoms lose energy and transform into more stable atoms. This process occurs spontaneously and releases radiation in the form of particles or electromagnetic waves.

How does radioactive decay occur in relativistic frames?

In relativistic frames, radioactive decay occurs at a slower rate compared to non-relativistic frames. This is due to the time dilation effect, where time passes slower for objects moving at high speeds. Therefore, the decay process appears to take longer in relativistic frames.

What is the half-life of a radioactive substance in a relativistic frame?

The half-life of a radioactive substance in a relativistic frame is the time it takes for half of the initial amount of radioactive material to decay. This can be calculated using the formula t1/2 = t0 / (1 - v2/c2), where t0 is the half-life in the rest frame and v is the velocity of the object.

Can radioactive decay be affected by the speed of the observer?

Yes, the speed of the observer can affect the rate at which radioactive decay occurs. This is because the observer's frame of reference can influence the measurement of time and therefore, the perception of how long the decay process takes.

Are there any other factors that can influence radioactive decay in relativistic frames?

In addition to the time dilation effect, other factors such as the strength of the gravitational field and the direction of motion can also affect radioactive decay in relativistic frames. These effects can be further studied through the theory of general relativity.

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