- #1
dwf
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What is time? This is a very hard question. Not even physics experts have a good anwser. I´d like to show you my ideas about this subject.
The measure of time is the measure of some standard events. I think we all agree with this. However, this thought lead us to think that, in a region with no events (therefore no exchange of energy), there is no time. I´ll show why this make sense. We can look to time in several different ways, as measure, as a dimension and as an operation. The operation time must generate a change in the physical system. In a region where there are no changes,the time operation would become a symmetry operation, so time would be frozen in that region. Formally,
T=R.E
Where R.E are the referential or standard events. But all events are a function of work, which is function of entropy, right?
So R.E=R.E(W(S)) where w=work and s=entropy. Taking the derivative, we find:
D(R.E)/ds= (R.E)´*(W)´
So
dt= (R.E)´*(W)´*ds
Also, we know that S=k ln(P) so ds=(k/p)dp
We can introduce this to quantum mechanics with the schrodinger equation:
After many calculations, we find that
-(h/2pi)²/(2m)*div(grad {y})+U(r)*y=ih/(2*pi)*(p/(R.E)´*(W)´*k*dp)*(dy-(<&y/&x,&y/&Y,&y/&z> * dr)
x,Y,z= space
t= time
h= Planck´s constant
U= potential energy
y= wave function
div = divergence operation
grad= gradient operation (div (grad)= laplacian)
R.E= referential events
W= work
k= Boltzmann constant
i= imaginary number (SQRT -(1))
p= number of possible states (thermodynamics concept)
What are the implications of this equation? Tell me your opinions about my idea.
The measure of time is the measure of some standard events. I think we all agree with this. However, this thought lead us to think that, in a region with no events (therefore no exchange of energy), there is no time. I´ll show why this make sense. We can look to time in several different ways, as measure, as a dimension and as an operation. The operation time must generate a change in the physical system. In a region where there are no changes,the time operation would become a symmetry operation, so time would be frozen in that region. Formally,
T=R.E
Where R.E are the referential or standard events. But all events are a function of work, which is function of entropy, right?
So R.E=R.E(W(S)) where w=work and s=entropy. Taking the derivative, we find:
D(R.E)/ds= (R.E)´*(W)´
So
dt= (R.E)´*(W)´*ds
Also, we know that S=k ln(P) so ds=(k/p)dp
We can introduce this to quantum mechanics with the schrodinger equation:
After many calculations, we find that
-(h/2pi)²/(2m)*div(grad {y})+U(r)*y=ih/(2*pi)*(p/(R.E)´*(W)´*k*dp)*(dy-(<&y/&x,&y/&Y,&y/&z> * dr)
x,Y,z= space
t= time
h= Planck´s constant
U= potential energy
y= wave function
div = divergence operation
grad= gradient operation (div (grad)= laplacian)
R.E= referential events
W= work
k= Boltzmann constant
i= imaginary number (SQRT -(1))
p= number of possible states (thermodynamics concept)
What are the implications of this equation? Tell me your opinions about my idea.