Heat conduction through a layers of different materials

In summary, The conversation discusses a question about a possible mistake in using the second equation to solve a problem. The expert explains that the area and k can be moved to the numerator using algebraic manipulation, but it is not applicable in this specific problem. The conversation is then moved to a different forum for further help in learning algebra.
  • #1
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Homework Statement


Question C(ii)
23513252_1863108113702914_1119620298_n.jpg

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Homework Equations


dQ/dt =-kA(dθ/dx)
dQ/dt = (θ12)/ ((lx/kxAx)+ (ly/kyAy))

The Attempt at a Solution


So the first time I tried at this question, I was using the second equation provided above,but when I check the answer, they put the area on the numerator. which left me wonder, how did they make it on top, I've check my textbook but none of it give any clues. If area is on the numerator with θ, I think k should be too isn't it?
 

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  • #2
If Ax = Ay = A, you can multiply numerator and denominator by A, so A will appear in the numerator and not the denominator. You can do the same with k if kx = ky, but that is not the case in this problem.
 
  • #3
I’ve moved this to the precalculus math forum where they can help you learn algebra.
 
  • #4
mjc123 said:
If Ax = Ay = A, you can multiply numerator and denominator by A, so A will appear in the numerator and not the denominator. You can do the same with k if kx = ky, but that is not the case in this problem.
I see, thanks for your answer
 

Related to Heat conduction through a layers of different materials

1. What is heat conduction?

Heat conduction is the transfer of thermal energy from one material to another through direct contact, without the movement of the material itself.

2. How does heat conduction occur through layers of different materials?

Heat conduction through layers of different materials occurs when there is a difference in temperature between the two materials. The heat energy flows from the higher temperature material to the lower temperature material until the temperatures equalize.

3. What factors affect heat conduction through layers of different materials?

The factors that affect heat conduction through layers of different materials include the thermal conductivity of the materials, the thickness of each layer, and the temperature difference between the layers.

4. How do you calculate heat conduction through layers of different materials?

The rate of heat conduction through layers of different materials can be calculated using the thermal conductivity of each material, the thickness of each layer, and the temperature difference between the layers. This can be done using the equation Q = kAΔT/Δx, where Q is the rate of heat transfer, k is the thermal conductivity, A is the surface area, ΔT is the temperature difference, and Δx is the thickness of the material.

5. What are some real-world examples of heat conduction through layers of different materials?

Some examples of heat conduction through layers of different materials include cooking food in a pan, melting wax in a candle, and using insulation in a building to keep it warm or cool.

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