Hawking Radiation: Theory & Evidence Behind Black Hole Emission

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In summary: EH of BH break up the pairs? ...if they do not come into existence with an enormous amount of velocity (near C), neither particle could ever escape from the gravity well of the BH.
  • #1
astro2cosmos
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as we know that nothing can escape from the black hole. but theory given by hawking for his radiation is fool proof or not. i mean he say that collision b/w particle and anti particle at the horizon emit the rays called radiation? then how we can say that these radiation are emitted from black hole?
 
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  • #2
It isn't the collision of between particles, but a creation of a pair of particles. Quantum fluctuations create a matter/antimatter pair of particles at the event horizon. Occasionally, one of the two falls into the event horizon before they can recombine. The other particle leaves.
Since the creation of the pair came from "borrowed" energy, the energy needed to maintain the existence of this particle must have come from somewhere. That somewhere is the mass of the black hole. To balance the energy books, the particle that falls into the black hole has a negative mass, and actually reduces the mass of the black hole. The result is that you see particles leaving the vicinity of the black hole while the black hole loses mass.
 
  • #3
but particle pair creation relies on the idea that they can only exist for less than the plank time before recombining into nothing. i think that implies that any gravitational influence experienced by one of the particles would also be experienced by the other particle, since the two cannot be physically very far apart - so the odds of one being sucked into, while the other escapes from, a BH seem extremely unlikely - any particle anywhere near the EH of a BH is oging to wind up inside the BH, unless it is somehow travleing at very very near C. i, and many others have long been skeptical of hawking radiation.
 
  • #4
not the plank time but time defined by HUP. Much, much longer!
 
  • #5
Janus said:
It isn't the collision of between particles, but a creation of a pair of particles. Quantum fluctuations create a matter/antimatter pair of particles at the event horizon. Occasionally, one of the two falls into the event horizon before they can recombine. The other particle leaves.
Since the creation of the pair came from "borrowed" energy, the energy needed to maintain the existence of this particle must have come from somewhere. That somewhere is the mass of the black hole. To balance the energy books, the particle that falls into the black hole has a negative mass, and actually reduces the mass of the black hole. The result is that you see particles leaving the vicinity of the black hole while the black hole loses mass.

excuse my lack of understanding, I'm not an educated physicist. Isn't there such a thing as quantum vacuum energy? like in the casimir experiment? don't these pairs of particles pop into existence everywhere, even very far away from any black hole
or other mass? so where does that energy come from? or do the equations still balance out because the particle anihilate and go back to nothing? and if it is a particle/antiparticle pair then would they not emit some energy gama ray or something when they anihilate?
 
  • #6
TalonD said:
1 Isn't there such a thing as quantum vacuum energy? like in the casimir experiment?
2 don't these pairs of particles pop into existence everywhere, even very far away from any black hole or other mass?
3 so where does that energy come from?
4 or do the equations still balance out because the particle anihilate and go back to nothing?
5 and if it is a particle/antiparticle pair then would they not emit some energy gama ray or something when they anihilate?

1 Yes, Casimir effect is explained by the virtual particles
2 Yes
3 From nowhere, virtual particles don't carry any free energy. They violate energy conservation law for small periods of time (obeying HUP)
4 yes, they go back to nothing because they don't carry free energy
5 and for that very reason they don't radiate - they don't have energy

The only difference near the horizon is horizon breaks the pairs, preventing the annihilation.
 
  • #7
how can being near the EH of BH break up the pairs? if they do not come into existence with an enormous amount of velocity (near C), neither particle could ever escape from the gravity well of the BH.
 
  • #8
Dmitry67 said:
1 Yes, Casimir effect is explained by the virtual particles
2 Yes
3 From nowhere, virtual particles don't carry any free energy. They violate energy conservation law for small periods of time (obeying HUP)
4 yes, they go back to nothing because they don't carry free energy
5 and for that very reason they don't radiate - they don't have energy

The only difference near the horizon is horizon breaks the pairs, preventing the annihilation.

jnorman said:
how can being near the EH of BH break up the pairs? if they do not come into existence with an enormous amount of velocity (near C), neither particle could ever escape from the gravity well of the BH.

so they don't have mass or energy unless a black hole pulls one of them in and then they do have mass and energy? one positive and one negative? That's strange, but then so many things are.

if a pair pops into existence near a black hole why would one get pulled in and not both considering how close together they must be to each other? there is such a fine balance in the gravity that it can pull one in and not the other? and why would the free one go flying off ? when they come into existence they don't have any speed or velocity relative to the black hole do they? or maybe they do? So why would the free one spontaneously go flying off away from the black hole? Well I'm sure Hawking has a complete mathmatical framwork describing the process so I accept it at face value, but it's just hard to imagine them not both being pulled in.
 
  • #10
talon - your questions at the end of your post are pretty much the same questions i am asking. while hawking may have laid out a mathematical possibility for something to occur, does not necessarily mean that it will actually happen.
 
  • #11
Perhaps not but that method is the basis for theoretical physics.
 
  • #12
funky - i am a pretty firm believer in the idea that if anything can possibly happen in this universe, it will happen. however, i just cannot see any possible way a particle created near the EH of a BH could ever escape the gravity well - can you?

and no, i cannot understand hawking's math. in fact, hawking is pretty much completely non-understandable to me with his more technical writings, eg "the nature of space and time" with penrose - penrose passages are clear, concise and understandable, while the chapters by hawking are fairly TOTALLY obtuse, confusing, and give me a headache trying to figure out quite what he is trying to say. how about you?
 

Related to Hawking Radiation: Theory & Evidence Behind Black Hole Emission

1. What is Hawking radiation?

Hawking radiation is a theoretical concept proposed by physicist Stephen Hawking in 1974. It suggests that black holes emit a type of radiation due to quantum effects near the event horizon, the point of no return for a black hole.

2. How does Hawking radiation work?

Hawking radiation is thought to occur when a pair of virtual particles, one with positive energy and one with negative energy, is created just outside the event horizon of a black hole. The negative energy particle falls into the black hole while the positive energy particle escapes, resulting in a loss of mass for the black hole.

3. What evidence supports the existence of Hawking radiation?

While direct observation of Hawking radiation is not yet possible, there is strong theoretical and indirect evidence for its existence. This includes the laws of thermodynamics, which predict that black holes should emit radiation, as well as observations of black hole candidates that show they are losing mass over time.

4. Can Hawking radiation cause a black hole to evaporate completely?

Yes, according to the theory, Hawking radiation can cause a black hole to lose mass over time and eventually evaporate completely. However, this process would take an extremely long time for large black holes, and for most black holes in the universe, the rate of radiation emission is very small compared to the rate of matter being pulled into the black hole by gravity.

5. Could Hawking radiation be harnessed as a source of energy?

In theory, yes, Hawking radiation could be harnessed as a source of energy. However, the amount of energy emitted by a black hole through Hawking radiation is very small and not practical for our current technology. Additionally, the process of extracting this energy would require advanced technology and would likely have negative effects on the black hole itself.

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