# Hard problem on partial differentiation

#### jaychay

##### Member

I have tried to do it many times but I end up getting the wrong answer.

#### jaychay

##### Member
I finally got the answer to the question.

#### skeeter

##### Well-known member
MHB Math Helper
$\dfrac{d}{dx}[f(x)h(x)] = f’(x)h(x) + f(x)h’(x)$

$\displaystyle f(x)h(x) = \int f’(x)h(x) \, dx + \int f(x)h’(x) \, dx$

$\displaystyle (x+1)^5 = \sin{x} + \int f(x)h’(x) \, dx$

finish it ...

#### Country Boy

##### Well-known member
MHB Math Helper
I think this is a problem on "integration by parts", NOT "partial differentiation".