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- Thread starter jaychay
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- Mar 1, 2012

- 1,053

$\displaystyle f(x)h(x) = \int f’(x)h(x) \, dx + \int f(x)h’(x) \, dx$

$\displaystyle (x+1)^5 = \sin{x} + \int f(x)h’(x) \, dx$

finish it ...

- Jan 30, 2018

- 916

I think this is a problem on "integration by parts", NOT "partial differentiation".