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I have posted a link there to this topic so the OP can see my work.Could Someone please take a look at this Calc 2 problem?!? Thank you so much!!!?

Solve 3 x y' - 6 y = x^{-4}, y(1) = -8.

(a) Identify the integrating factor, alpha(x).

I know in a) alpha(x) = e^(-2ln(abs(x)))

But I am not sure how to do parts (b) and (c).

(b) Find the general solution.

y(x) = ?

(c) Solve the initial value problem y(1) = -8

y(x) = ?

Thank you so much for your help!!!!!!