Okay, so we have:yes, the first term is $12x^2y^3$
If it is factorable it will work. I would hesitate to say there is an "always will work" method when it comes to factoring. Factoring is a skill that requires a great deal of trial and error at times, but as you develop experience, you become better at it.uhm it sounds difficult. but will that method always works in this type of problem.