Ground state of 7 electrons in infinite square well

In summary: I do it all the time.In summary, the ground state energy of a system of 7 electrons trapped in a one dimensional infinite square well is 22 times h2 / 8mL2. This is calculated by considering the Pauli exclusion principle and the possible quantum numbers for the electrons. The mistake in the original attempt at a solution was assuming an angular momentum number for the 1-D infinite well, when in fact there are only two states for each energy level.
  • #1
sabinscabin
11
0

Homework Statement



Seven electrons are trapped in a one dimensional infinite square well of length L. What is the ground state energy of this system as a multiple of h2 / 8mL2?

Homework Equations


Energy of a single electron in state n is n2h2 / 8mL2

The Attempt at a Solution



Pauli exclusion principle says all 7 must have different quantum numbers.
starting from n = 1, we have L = 0 and mL = 0, and ms = -1/2 and 1/2, so there are two electrons in n = 1.
For n = 2, we have two electrons for L = 0
for L = 1, we have mL = -1, 0, 1, which means this subshell can hold 6 electrons. The remaining 3 electrons go into this subshell then.

Final tally: 2 electrons for n = 1 and 5 electrons for n = 2.

Total energy as a multiple of the given term then = 2*1^2 + 5*2^2 = 22.

Halliday Resnick says 44 for some reason. Can anybody spot my mistake?
 
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  • #2
Hi sabinscabin,

sabinscabin said:

Homework Statement



Seven electrons are trapped in a one dimensional infinite square well of length L. What is the ground state energy of this system as a multiple of h2 / 8mL2?


Homework Equations


Energy of a single electron in state n is n2h2 / 8mL2


The Attempt at a Solution



Pauli exclusion principle says all 7 must have different quantum numbers.
starting from n = 1, we have L = 0 and mL = 0, and ms = -1/2 and 1/2, so there are two electrons in n = 1.
For n = 2, we have two electrons for L = 0
for L = 1, we have mL = -1, 0, 1, which means this subshell can hold 6 electrons. The remaining 3 electrons go into this subshell then.

Final tally: 2 electrons for n = 1 and 5 electrons for n = 2.

Total energy as a multiple of the given term then = 2*1^2 + 5*2^2 = 22.

Halliday Resnick says 44 for some reason. Can anybody spot my mistake?

For the 1-D infinite well, there are only two states for each energy level (corresponding to the two spin values).
 
  • #3
ah thanks. That was incredibly stupid of me. It's in a square well so there's no angular momentum number since there's nothing to orbit.

D'oh!
 
  • #4
No, not stupid. The important thing is to understand why something is wrong. If the test of stupidity is making a mistake, I'm in a lot of trouble.
 

Related to Ground state of 7 electrons in infinite square well

1. What is the ground state of 7 electrons in an infinite square well?

The ground state of 7 electrons in an infinite square well is the lowest possible energy state that the electrons can occupy within the well. It is also known as the lowest energy level or the n=1 energy level.

2. How is the ground state of 7 electrons in an infinite square well calculated?

The ground state energy of 7 electrons in an infinite square well can be calculated using the Schrödinger equation and the boundary conditions of the well. This involves solving for the wave function of the system and finding the corresponding energy eigenvalue.

3. What is the significance of the ground state in the context of quantum mechanics?

The ground state is significant in quantum mechanics as it represents the most stable and lowest energy state that a system can exist in. All other energy states are measured relative to the ground state and it serves as a reference point for understanding the behavior and properties of a system.

4. Can the ground state of 7 electrons in an infinite square well be degenerate?

Yes, the ground state of 7 electrons in an infinite square well can be degenerate, meaning there can be more than one possible wave function and energy eigenvalue that satisfy the Schrödinger equation and boundary conditions. This is dependent on the shape and size of the well.

5. How does the ground state of 7 electrons in an infinite square well differ from the ground state of a single electron in the same well?

The ground state of 7 electrons in an infinite square well is characterized by multiple energy levels and wave functions, whereas the ground state of a single electron only has one energy level and one corresponding wave function. Additionally, the energy of the ground state for 7 electrons will be lower than that of a single electron due to the repulsion between the electrons in the well.

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