What was the elapsed time of the flight stone?

In summary, a stone is thrown vertically upward with a velocity of 26.0 m/s from the top of a tower having a height of 18.5m. On it's return it misses the tower and finally strikes the ground. The elapsed time of the flight stone is 2.65s.
  • #1
ffrpg
12
0
Here's the question, A stone is thrown vertically upward with a velocity of 26.0 m/s from the top of a tower having a height of 18.5m. On it's return it misses the tower and finally strikes the ground. What was the elapsed time of the flight stone?


I started if off with delta y= 26t+1/2(-9.91)t^2. From there I derived that forumula getting 26+0.81t=0. Solved for t, got 2.65s. I plugged t into the first formula and got 34.35. To get the other half of the time the stone was in the air I used 26t_2+1/2(-9.81)t_2^2. I solved for t_2 and added it with 34.45, but didn't end up with the correct answer. Where did I go wrong?
 
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  • #2
From you calculations I can't see your "battle plan". here's mine.
1. find out how much time does it take the stone to stop. v=g*t1
2. it takes it the same amount of time to fall to the top of the tower.
3. find out how long does it take from here to hitting the ground. h=v*t2 + g*t22/2.
4. finally t=2*t1+t2
 
  • #3
Your solution is almost right. First instead of using
"delta y= 26t+1/2(-9.91)t^2", you can simply add the known initial height (18.5 m) to say y= 18.5+ 26t+1/2(-9.91)t^2 where y is height above the ground.

Now, DON'T differentiate to get velocity: you don't need to find the highest point, that's not asked. Since y IS the height above the ground, the problem is simply asking "what is t when y= 0?" In other words, solve the equation 18.5+ 26t+1/2(-9.91)t^2= 0.
Since this is a quadratic, it will have two solutions. You only want the positive one.
 
  • #4
I alright I tried what you said and ended up with 46.14 s. Is that correct?
 
  • #5
The Mentors's answer is perfect. You dervived a relation when you are not allowed to and you did it wrong. By solving the second degree equation, as I and my friend did, the result is 5.9 s. Using the day to day numerical values for the heigt and the speed of the stone, this amount of time is really belivable.
 
  • #6
I have no idea how you got "46.14 s" but it is certainly not correct. Plugging it into the equation,18.5+ 26t+1/2(-9.91)t^2 = 0,
we get 18.5+ 26(45.14)+1/2(-9.91)(46.14)^2= 18.5+ 1199.64- 10548.70=
-9330.66 NOT 0!

Use the quadratic formula!
 

1. What is the definition of elapsed time?

The elapsed time refers to the total amount of time that has passed since the start of an event or process.

2. How is the elapsed time of a flight stone calculated?

The elapsed time of a flight stone can be calculated by subtracting the departure time from the arrival time. This will give the total amount of time the stone was in flight.

3. What units are used to measure elapsed time?

Elapsed time is typically measured in units of seconds, minutes, hours, or days.

4. Why is it important to measure the elapsed time of a flight stone?

Measuring the elapsed time of a flight stone can provide valuable information about the speed and efficiency of the stone's flight. It can also help track the location and trajectory of the stone.

5. Are there any factors that can affect the accuracy of the elapsed time measurement for a flight stone?

Yes, there are several factors that can affect the accuracy of the elapsed time measurement for a flight stone. These include wind resistance, air density, and the shape and weight of the stone.

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