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Andy SV
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Would a hollow sphere measure the same gravitationally as a solid sphere if it was the same mass?
Just sharing an interesting question
Just sharing an interesting question
Andy SV said:Just sharing an interesting question
Andy SV said:Would a hollow sphere measure the same gravitationally as a solid sphere if it was the same mass?
Arkalius said:if you are inside a hollow sphere that has uniform density and thickness, you will experience no net gravitational force from the sphere from anywhere within it
The main difference between the gravity of a hollow sphere and a solid sphere of the same mass is that the hollow sphere has a zero gravity field inside, while the solid sphere has a non-zero gravity field throughout its volume. This means that an object placed inside the hollow sphere will experience no gravitational force, while an object placed inside the solid sphere will experience a gravitational force towards the center of the sphere.
The distribution of mass within a sphere has a significant impact on its gravity. In a solid sphere, the mass is evenly distributed, resulting in a constant gravity field throughout the sphere. In a hollow sphere, the mass is concentrated at the outer surface, resulting in a zero gravity field within the sphere.
The gravitational force is stronger for a solid sphere than a hollow sphere of the same mass. This is because the solid sphere has a non-zero gravity field throughout its volume, while the hollow sphere only has a gravity field at its outer surface.
The radius of a sphere has a direct impact on its gravitational force. As the radius increases, the distance between objects on the surface and the center of the sphere also increases, resulting in a weaker gravitational force. However, for a sphere with a fixed mass, the gravitational force at its surface will remain the same regardless of its radius.
No, the shape of a sphere does not affect its gravitational force as long as the mass and radius remain constant. This is because the gravitational force is determined by the mass and distance between objects, not the shape of the sphere.