Gravitational potential energy released in core collapse

In summary, the task is to estimate the gravitational potential energy released in the collapse of a 1.2 solar-mass core, starting from an initial density of 10^9 g/cm^3 and ending at a final density of 10^15 g/cm^3. The equation PE = - GM / r can be used, along with the given densities and the formula for volume (4/3) Pi r^3. The final calculation requires finding the change in radius.
  • #1
creepypasta13
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Homework Statement



Estimate the gravitational potential energy released in the collapse of a 1.2 solar-mass core from an initial density of 10^9 g/cm^3 to a final 10^15 g/cm^3.

Homework Equations


The Attempt at a Solution



The book doesn't provide much guidance on this. I was thinking of using q= 3/5 assuming the density is constant. Then manipulate M^2/R to Rho*(M)*(R^2)*(4pi/3). And plug in the values for Rho that are given and substitute 1.2 for M. But there's no mention of what the radius is. Do I just use the solar-radius?

Never mind the above. I think I computed it correctly.

Mods, feel free to close this thread
 
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  • #2
Maybe you can apply: PE = - GM / r.

Use mass = density X volume. Mass is given (1.2 X mass of sun). Densities are given.

Volume = (4/3) Pi r^3. You can find the change in radius.
 

Related to Gravitational potential energy released in core collapse

1. What is gravitational potential energy released in core collapse?

Gravitational potential energy released in core collapse is the energy released when a massive star runs out of fuel and collapses under its own gravity. This collapse causes the star's core to become extremely dense and hot, leading to various explosive events such as supernovae.

2. How is gravitational potential energy released in core collapse calculated?

The amount of gravitational potential energy released in core collapse is calculated using the mass of the star, the radius of the star's core, and the gravitational constant. The equation is E = -(3/5)GM^2/R, where E is the energy released, G is the gravitational constant, M is the mass of the star, and R is the radius of the core.

3. Why is gravitational potential energy released in core collapse important?

The release of gravitational potential energy in core collapse plays a crucial role in the evolution of stars and the universe. It powers explosive events such as supernovae and can also lead to the formation of black holes. This energy is also essential for the formation of new stars and the creation of heavy elements that make up our planet and all life on it.

4. What is the difference between gravitational potential energy and kinetic energy in core collapse?

Gravitational potential energy is the energy stored in an object due to its position in a gravitational field, while kinetic energy is the energy an object possesses due to its motion. In core collapse, as the star's core collapses, gravitational potential energy is converted into kinetic energy, causing the core to become extremely hot and dense.

5. Can gravitational potential energy released in core collapse be harnessed for human use?

No, the amount of gravitational potential energy released in core collapse is far too immense for human use and is also extremely dangerous. The energy released in core collapse can cause massive explosions and destruction, making it impossible to harness for human use. However, scientists are studying ways to better understand and possibly harness this energy for space exploration and other purposes in the future.

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