Gravitational force of the sun on earth

In summary: The value of r stays the same in both cases. In summary, the system of the Sun, Earth, and Moon can be simplified to just the Sun and Earth. The gravitational force of the Sun on the Earth is calculated using the equation Fg = (Gm1m2) / (r^2), where m1 is the mass of the Sun, m2 is the mass of the Earth, and r is the distance between their centers. This value is the same as the force of the Earth on the Sun, according to Newton's 3rd Law of Motion. The value of r stays the same in both cases.
  • #1
tquiva
20
0

Homework Statement


Consider the system of the Sun, Earth, and Moon, at a moment in time when they happen to be exactly in a line. (Assume that all distances d are measured between the centers of all bodies, and that all distances d are much greater than the radii of all bodies.
M(sun) = 1.99e30 kg
M(earth) = 5.97e25 kg
M(moon) = 7.35e22 kg
d(earth-sun) = 1.50e11 m
d(earth-moon) = 3.84e8 m
G = 6.67e-11 Nm^2/kg^2

Calculate the magnitude of the gravitational force of the Sun on the Earth. Also, what is the gravitational force of the Earth on the Sun?

Homework Equations


Fg = (Gm1m2) / (r^2)


The Attempt at a Solution


I know that all I have to do is plug in the value into the Fg equation above. However, I'm a little lost with the force of the Sun on the Earth, and the force of the Earth on the sun. Does the value of r change for both of these cases or stay the same?
 
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  • #2
If you forget Moon for a moment, then the force of Sun on Earth should be the same as the force of Earth on Sun.
If you do not forget Moon, those forces are still the same, but there is the force of the Moon as well, so the sum force acting on Earth is F(Sun-Earth) + F(Moon-Earth). In a vector sense, so you should substract the force by Moon if it is in the other side. I suspect from the wording that it is on the other side, but it is not exactly clear.
 
  • #3
The force of the Sun on the Earth is the same as the force of the Earth on the Sun. It must be, according to Newton's 3rd Law of Motion.
 

Related to Gravitational force of the sun on earth

1. What is the gravitational force of the sun on earth?

The gravitational force of the sun on earth is approximately 274 meters per second squared (m/s²). This value is known as the standard gravitational parameter and is used to calculate the force of gravity between any two objects.

2. How does the gravitational force of the sun affect the earth?

The gravitational force of the sun is responsible for keeping the earth in its orbit around the sun. It also causes the tides on earth and affects the trajectory of objects in space, such as comets and asteroids.

3. Does the gravitational force of the sun vary on different parts of earth?

Yes, the gravitational force of the sun does vary on different parts of earth due to variations in the earth's distance from the sun and its rotation. For example, the force is slightly stronger at the poles compared to the equator.

4. How does the gravitational force of the sun compare to other forces on earth?

The gravitational force of the sun is one of the strongest forces on earth, second only to the force of the earth's own gravity. It is much stronger than other forces such as electromagnetic and nuclear forces.

5. Can the gravitational force of the sun ever be completely eliminated on earth?

No, the gravitational force of the sun cannot be completely eliminated on earth. Even if all objects on earth were somehow removed, the force of the sun's gravity would still be present. However, its effects would be greatly reduced without the presence of other objects.

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