denverdoc said:I would think that's as close as the two could come together and therefore the greatest force would be generated. You seem to imply that this is not the case?
denverdoc said:you have .44 above when the problem states .4, and .148 instead of .158 as you suggested using in the denom. maybe follow suit and go to bed as I intend to now.
The gravitational force between two bowling balls is dependent on their masses and the distance between them. The equation to calculate this force is F = (G * m1 * m2) / d^2, where G is the gravitational constant, m1 and m2 are the masses of the two balls, and d is the distance between them.
The gravitational force between two objects is directly proportional to their masses. Since bowling balls are typically larger and heavier than billiard balls, the gravitational force between them will be greater. However, this force is still relatively small and is often overshadowed by other forces in real-life scenarios.
No, the gravitational force between two objects can never be negative. This is because gravity is always attractive, meaning that it always pulls objects towards each other. If the masses are opposite in sign, the force will still be positive since the negative sign will cancel out when multiplied with the other negative mass.
The gravitational force between two objects is inversely proportional to the square of the distance between them. This means that as the distance between the two bowling balls increases, the force between them decreases. This relationship is known as the inverse-square law and is applicable to all objects with mass.
The gravitational constant, denoted by G, is a fundamental constant in physics that is used to calculate the gravitational force between two objects. Its value is approximately 6.674 x 10^-11 N*m^2/kg^2. Without this constant, it would be impossible to accurately calculate the gravitational force between objects of varying masses and distances.