- #1
Living_Dog
- 100
- 0
At the very bottom of the page they have that the straight line, using the definition of a vector as the derivative of the worldline is given as:
[tex]P(0) + \lambda(\frac{dP}{d\tau})_o[/tex]
But since the worldline, [tex]P(\tau)[/tex] is paramtrized by [tex]\tau[/tex] and not [tex]\lambda[/tex], then shouldn't the equation be:
[tex]P(0) + \tau(\frac{dP}{d\tau})_o[/tex]
?
Thanks in advance.
[tex]P(0) + \lambda(\frac{dP}{d\tau})_o[/tex]
But since the worldline, [tex]P(\tau)[/tex] is paramtrized by [tex]\tau[/tex] and not [tex]\lambda[/tex], then shouldn't the equation be:
[tex]P(0) + \tau(\frac{dP}{d\tau})_o[/tex]
?
Thanks in advance.