Grade 11 acceleration problem?

[SoConfused__]

Homework Statement

Jack went up a hill to fetch water. Jack fell down and rolled down the hill accelerating at 0.65 m/s^2 down. If he rolled 11m down the hill in 3.7s, with what velocity was he moving when he fell?

Homework Equations

a = v2 - v1/t
v2 = at + v1

The Attempt at a Solution

(0.65m/s^2)(3.7s) + 11
= 13.5 m/s.

I solved for v2, the velocity when he reached the bottom of the hill.
However the answer says 1.8m/s.
What am I doing wrong? Am I supposed to be looking for something else, not v2?
Even if I solved for v1, I would get a negative answer.

As usual, I am so confused.

 

[xcvxcvvc]

try this
[tex]R(t) = \frac{1}{2}at^2+v_it+R_i[/tex]
[tex]v_i = \frac{R(t) - \frac{1}{2}at^2-R_i}{t}[/tex]

 

[SoConfused__]

That confuses me even more. What does R stand for?

 

[PhanthomJay]

Homework Statement

Jack went up a hill to fetch water. Jack fell down and rolled down the hill accelerating at 0.65 m/s^2 down. If he rolled 11m down the hill in 3.7s, with what velocity was he moving when he fell?

Homework Equations

a = v2 - v1/t
v2 = at + v1

The Attempt at a Solution

(0.65m/s^2)(3.7s) + 11

what's that 11, that's a length unit, not a speed unit.

I solved for v2, the velocity when he reached the bottom of the hill.
However the answer says 1.8m/s.
What am I doing wrong? Am I supposed to be looking for something else, not v2?

you are supposed to be looking for the initial velocity when he fell.

Even if I solved for v1, I would get a negative answer.

and what would the negative sign imply?