Goldfish bowl index of refraction

[tiger1]

Homework Statement

To a fish in an aquarium, the 4.30 mm-thick walls appear to be only 3.10 mm thick.
What is the index of refraction of the walls?

Homework Equations

m=-s'/s
n_1/s + n_2 / s' = (n_2-n_1)/R
m: magnification
s: object distance
s': image distance

The Attempt at a Solution

m=(3.1/4.3)=.72
m=-s'/s
n_1/s + n_2 / s' = (n_2-n_1)/R
1.33/s + n_2/s' = (n_2-1.33)/R

I'm not sure what R, s, or s' would be.
If I plug in the numbers I received from determing the magnification, I receive this:

1.33/4.33 + n_2/3.1 = (n_2 - 1/33)/R

 

[Nate810]

I'm not sure if this is the correct equation to solve for the index of refraction or if I'm missing something. Any help is appreciated.

 

[tomcue]

I cannot determine the index of refraction without knowing the values for R, s, and s'. The given information does not provide enough information to solve for these parameters. Additionally, the equations used in the attempt at a solution are not directly applicable to this situation. The index of refraction is a property of the material the light is passing through, not the magnification of the image. Therefore, without further information, it is not possible to determine the index of refraction of the walls in this scenario.