Dec 2, 2020 Thread starter #1 S solakis Active member Dec 9, 2012 352 Given an isosceles trigon ABC (AC=AB),take apoint on AB ,D and between the points A and B,then prove: $(CD)^2=(BD)^2+\dfrac{(BC)^2(AD)}{AB}$
Given an isosceles trigon ABC (AC=AB),take apoint on AB ,D and between the points A and B,then prove: $(CD)^2=(BD)^2+\dfrac{(BC)^2(AD)}{AB}$
