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- Thread starter taitu
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- Jan 29, 2012

- 1,151

Isn't "x^2*2016x" the same as "2016x^3"?

- Mar 1, 2012

- 639

https://mathhelpforum.com/threads/functions-problem.285171/#post-954658

very good hint was given to determine $f(2017)$

- Jan 29, 2012

- 1,151

f(x^2- 2016x)= f(2017) if x^2- 2016x= 2017. That is the same as x^2- 2016x- 2017= (x+ 1)(x- 2017)= 0 so either x= -1 or x= 2017.

So either f(2017)= -1(f(-1))+ 2016 or f(2017)= 2017 f(2017)+ 2016.

For the latter, -2016= 2016 f(2017) so f(2017)= -1.