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- Thread starter AndreArgo
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Hello, and welcome to MHB!Y=f(x)

which passes through points:

(-1,3) and (0,2) and (1,0) and (2,1) and (3,5)

second function is defined: g(x)=2f(x-1)

Calculate g(0)

Calculate g(1)

Calculate g(2)

Calculate g(3)

We are given:

\(\displaystyle g(x)=2f(x-1)\)

We are also given 5 points in the form:

\(\displaystyle (x,f(x))\)

And so:

\(\displaystyle g(0)=2f(0-1)=2f(-1)=2\cdot3=6\)

Does that make sense? Can you continue?

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Just figured it out. Thank you MarkHello, and welcome to MHB!

We are given:

\(\displaystyle g(x)=2f(x-1)\)

We are also given 5 points in the form:

\(\displaystyle (x,f(x))\)

And so:

\(\displaystyle g(0)=2f(0-1)=2f(-1)=2\cdot3=6\)

Does that make sense? Can you continue?