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Fun Logic Puzzle!

alane1994

Active member
Oct 16, 2012
126
There are 111 people in a competition. The competition has 4 boxes and 4 jewels. Each box is identical and is completely opaque (i.e. you cannot see inside the box once it is closed). The jewels are all different: diamond, ruby, emerald and topaz. Everyone in the competition knows this. The host (who is NOT one of the 111 taking part), places one jewel in each box and then seals the boxes and writes a letter on each box: A, B, C and D - all done WITHOUT any of the 111 competitors watching. The competitors are then asked to guess which jewel is in which box.

-9 people get all 4 of their guesses wrong
-15 people guess exactly one jewel correctly
-25 people guess exactly 2 jewels correctly

How many people:
a) guess exactly 3 jewels correctly
b) guess exactly 4 jewels correctly

Bit of a hey, I'm back.... again.... puzzle!
 

alane1994

Active member
Oct 16, 2012
126
If you want a hint, feel free to ask! :)
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
My solution:

Since it is impossible to guess only 3 correctly, that leaves the remaining 62 to have guessed all 4 correctly.
 

eddybob123

Active member
Aug 18, 2013
76
My solution:

Since it is impossible to guess only 3 correctly, that leaves the remaining 62 to have guessed all 4 correctly.
Unless one or more people guessed twice of the same jewel, so they would have a slightly higher chance of guessing one of those right. But it