Frictionless ramp, constant velocity, find work

In summary, this is a conservation of energy problem where the work done by the movers pushing the piano up a 1.73 m high frictionless ramp is equal to the potential energy gained by the piano. The work can be calculated using the equation K + U (before) = K + U (after) where K is kinetic energy, U is potential energy, m is the mass of the piano, v is the velocity, g is the acceleration due to gravity, and h is the height of the ramp. The answer should be provided in kilo-Joules (kJ).
  • #1
holls14
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Homework Statement



Movers must push a piano onto a truck, the bed of which is a height 1.73 m above the ground. To do this they will use a frictionless ramp. If the piano has a mass of 1635.0 kg and the movers push it up the slope at a constant velocity, how much work do they need to do on it to move it into the bed? Please provide your answer in kilo-Joules (kJ), as the amount of work should be quite large.


Homework Equations





The Attempt at a Solution


I have no clue where to start here, no angle?
 
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  • #2
holls14 said:

Homework Statement



Movers must push a piano onto a truck, the bed of which is a height 1.73 m above the ground. To do this they will use a frictionless ramp. If the piano has a mass of 1635.0 kg and the movers push it up the slope at a constant velocity, how much work do they need to do on it to move it into the bed? Please provide your answer in kilo-Joules (kJ), as the amount of work should be quite large.


Homework Equations





The Attempt at a Solution


I have no clue where to start here, no angle?

Do not think of it as a dynamics problem with forces (i.e. you don't need an angle). This is a conservation of energy problem. The work you put into the moving the piano up 1.73 m turns into potential energy. If we think of it in reverse, the potential energy of the piano afterwards is equal to the _______ .

K + U (before) = K + U (after)

where K is kinetic energy and U is potential energy.

K = (1/2)mv2
U = mgh
 

Related to Frictionless ramp, constant velocity, find work

1. How is work calculated on a frictionless ramp with constant velocity?

Work is calculated by multiplying the force applied to an object by the distance it moves in the direction of the force. In a frictionless ramp with constant velocity, the force and distance are both constant, so the work done is simply the product of these two values.

2. Does friction play a role in the work done on a frictionless ramp with constant velocity?

No, friction does not play a role in the work done on a frictionless ramp with constant velocity. This is because there is no force opposing the motion, so there is no work being done against friction.

3. What is the relationship between work and energy on a frictionless ramp with constant velocity?

On a frictionless ramp with constant velocity, the work done on an object is equal to the change in kinetic energy of the object. This is known as the work-energy theorem.

4. Can the work done on an object on a frictionless ramp with constant velocity be negative?

No, the work done on an object on a frictionless ramp with constant velocity cannot be negative. This is because the force and distance are both in the same direction, so the work done will always be positive.

5. How does the angle of the ramp affect the work done on an object with constant velocity?

The angle of the ramp does not affect the work done on an object with constant velocity. As long as the ramp is frictionless and the velocity is constant, the work done will remain the same regardless of the angle of the ramp.

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