Frictional force is independent of the area of contact

In summary, one of the laws of friction states that the frictional force is independent of the area of contact and velocity. However, this particular law is only approximately true. The force of friction is determined by the equation F = Mu * Fn, where Mu is a unit-less constant and Fn is the normal force. This means that the force of friction does not directly depend on the area of contact. However, in real life scenarios, the force of friction can be affected by the size and shape of the contact patch, resulting in a non-uniform coefficient of friction. Therefore, while the law of friction may hold true in ideal situations, it is not always accurate in real world applications.
  • #1
monty37
225
1
one of the laws of friction states that the frictional
force is independent of the area of contact,and velocity,how true is this?
my book says this particular law is only approximately true.
 
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  • #2


monty37 said:
one of the laws of friction states that the frictional
force is independent of the area of contact,and velocity,how true is this?
my book says this particular law is only approximately true.

As far as I know, when one says friction does not depend on the area of contact, they do it by looking at the equation for the force of friction.

[tex]F = \mu F_n[/tex]

So the force of friction depends only on the unit-less constant Mu and normal force. Neither of these things depends on the area, so we say the force of friction doesn't depend on area.

Someone might be able to give a deeper understanding of why, but that's how I've always thought of it.
 
  • #3


It's possible to understand roughly in this way: Divide the surface area of the floor into small pieces. Now, the number of these tiny pieces that are pushing the block is proportional to A, the contact area, but the force that each of these little pieces applies to the object is proportional to the pressure exerted on the floor at that point, i.e. to N/A (where N is the normal force), so the total friction force is proportional to A(N/A) = N.
 
  • #4


Another way of looking at it: all of the properties of the contact patch, including its area, are contained in the friction coefficient.
 
  • #5


monty37 said:
one of the laws of friction states that the frictional
force is independent of the area of contact,and velocity,how true is this?
my book says this particular law is only approximately true.
The book is correct, it's just an approximation that doesn't apply in real life, especially if the objects get reasonably small. This is discussed and demonstrated as an off topic subject in the second half of video #2 in this series on gyroscopes:

http://www.gyroscopes.org/1974lecture.asp

In that video, the smaller but otherwise identical (same density) "cubes" have a much higher static coefficient of friction.

In the case of tires, load sensitivity causes coefficient of friction to decrease with load, so larger tires are better until weight, drag, or other factors become an issue. (Larger tires also allow for more heat dissapation in race car).

http://en.wikipedia.org/wiki/Tire_load_sensitivity
 
  • #6


The way I remember it ('88 grad) - you have two types of friction:
Static - this is related to the force necessary to get a stationary object to move from rest.
Dynamic - this is related to the force necessary to sustain a moving object at a constant velocity. Does the question pertain to both phases of friction or just one?
 
  • #7


russ_watters said:
Another way of looking at it: all of the properties of the contact patch, including its area, are contained in the friction coefficient.

That would imply that the co-efficient of friction between the same pair of materials would vary with the area of contact, which is not the case.

dx said:
It's possible to understand roughly in this way: Divide the surface area of the floor into small pieces. Now, the number of these tiny pieces that are pushing the block is proportional to A, the contact area, but the force that each of these little pieces applies to the object is proportional to the pressure exerted on the floor at that point, i.e. to N/A (where N is the normal force), so the total friction force is proportional to A(N/A) = N.

This makes good sense.
 
  • #8


Shooting Star said:
That would imply that the co-efficient of friction between the same pair of materials would vary with the area of contact, which is not the case.

Actually, this is the case. It probably varies with materials, but one example is car tires on asphalt. High performance cars have wider tires to increase the size of the contact patch and in turn the coefficient of friction. Maybe this is a different case since the rubber is compliant and can be squeezed into the surface of the not-perfectly-smooth asphalt, but my college physics book also states that the coefficient of friction takes into account the area (and other factors, like whether or not one material is compliant and can squeeze into cracks of the other material). If your area of contact changes, you might need a new coefficient of friction, depending on the materials, allowable error, etc.

-Kerry
 
  • #9


KLoux said:
Actually, this is the case. It probably varies with materials, but one example is car tires on asphalt. High performance cars have wider tires to increase the size of the contact patch and in turn the coefficient of friction. Maybe this is a different case since the rubber is compliant and can be squeezed into the surface of the not-perfectly-smooth asphalt, but my college physics book also states that the coefficient of friction takes into account the area (and other factors, like whether or not one material is compliant and can squeeze into cracks of the other material). If your area of contact changes, you might need a new coefficient of friction, depending on the materials, allowable error, etc.

-Kerry

This is something that bothered me a bit (like your tire example). How is Mu calculated between material A and A'? Testing it would be an easy method. Suppose A and A' are made of the same materials, but A' is twice the length and width of A. Would A''s coefficient of friction be larger than A's in the real world? If so, then Mu is dependent on the area, and thus the force of friction does as well.
 
  • #10


Pupil said:
This is something that bothered me a bit (like your tire example). How is Mu calculated between material A and A'? Testing it would be an easy method. Suppose A and A' are made of the same materials, but A' is twice the length and width of A. Would A''s coefficient of friction be larger than A's in the real world? If so, then Mu is dependent on the area, and thus the force of friction does as well.

These kind of experiments are common in a first year mechanics course, and show that the coefficient of friction is not correlated with the area of contact. Of course, when I performed the experiments it was in a crumby little lab and any small effects would have been completely surpassed by experimental error, so at most I can say is that there is a very loose correlation if at all.

The example of a racecar's tires was explained to me to have to due with things other than just normal sliding friction. It was explained to me that because the tires got so hot from friction, the rubber became, in a sense, sticky, which gave rise to a different force which is correlated with contact area.
 
  • #11


Shooting Star said:
That would imply that the co-efficient of friction between the same pair of materials would vary with the area of contact, which is not the case.

KLoux said:
Actually, this is the case. It probably varies with materials, but one example is car tires on asphalt. High performance cars have wider tires to increase the size of the contact patch and in turn the coefficient of friction.
-Kerry

No, it is not the case in the regime where the laws of static and dynamic friction are valid -- otherwise those laws woudn't exist. I was not consideiing rolling friction, so the tire scenario is not very pertinent to my point..

This point is well exemplified by Pupil in post #9.
 
  • #12


Shooting Star said:
It is not the case in the regime where the laws of static and dynamic friction are valid -- otherwise those laws woudn't exist.
They're not laws, but instead simplifications of a real life situation, similar to Bernoulli equation being a simplified case of the more accurate Navier-Stokes equations. Please watch the 2nd half of the video #2:

http://www.gyroscopes.org/1974lecture.asp

A clean flat plate with 4 solid blocks of varying sizes is angled upwards, and the larger blocks begin sliding well before the smaller blocks. The smaller blocks exhitbit a higher coefficient of friction with the flat plate, demonstrating some form of load senstitivy (the smaller blocks exert a smaller force per unit area).

From wiki:

though in general the relationship between normal force and frictional force is not exactly linear :

http://en.wikipedia.org/wiki/Friction
 
  • #13


The tire scenario is a static friction scenario. Yes, it is usually true that static friction does not vary with contact area, but the OP said:
...my book says this particular law is only approximately true.
...and static friction in tires is one example where it is not true.

I suppose there is no single set of equations that people generally refer to for friction, but one could write one with separate terms for how friction force varies with area. In cases where it doesn't those terms would simply cancel out, similar to the way Bernouli's equation is used.
 
  • #14


when the area of contact becomes lesser,pressure increases and then the law does not
hold true,and is this not the case for all kinds of friction:rolling,sliding,static,dynamic?
 
  • #15


(Sorry for the delayed post.)
Jeff Reid said:
They're not laws, but instead simplifications of a real life situation, similar to Bernoulli equation being a simplified case of the more accurate Navier-Stokes equations. Please watch the 2nd half of the video #2:

http://www.gyroscopes.org/1974lecture.asp
I believe that applies to all the laws of science. The point was that the equation for static fiction holds quite true within a narrow regime. Or does it? The video was most illuminating.
russ_watters said:
The tire scenario is a static friction scenario.
Yes, my oversight. I was thinking of something else.
I suppose there is no single set of equations that people generally refer to for friction, but one could write one with separate terms for how friction force varies with area. In cases where it doesn't those terms would simply cancel out, similar to the way Bernouli's equation is used.
Could you give a simple example where the area is explicitly involved and which would reduce to an area-independent equation for simple cases?
 

Related to Frictional force is independent of the area of contact

1. What is frictional force?

Frictional force is a force that opposes motion between two surfaces in contact with each other.

2. How is frictional force affected by the area of contact?

Frictional force is independent of the area of contact, meaning that the amount of surface area in contact between two objects does not affect the strength of the frictional force.

3. Why is frictional force independent of the area of contact?

This is because friction is caused by the roughness of the surfaces in contact, not the amount of surface area. Therefore, the strength of the frictional force remains the same regardless of the size of the area in contact.

4. Does the type of surface affect the frictional force?

Yes, the type of surface does affect the frictional force. Rougher surfaces have more frictional force compared to smoother surfaces because there are more microscopic bumps and ridges that interact and create resistance against motion.

5. Can frictional force be reduced?

Yes, frictional force can be reduced by using lubricants or by polishing the surfaces in contact to make them smoother. This reduces the amount of resistance between the surfaces and decreases the strength of the frictional force.

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