- #1
demonslayer42
- 18
- 0
Homework Statement
A 40 kg block slides down arough incline of 35 degrees with a constant velocity. Find the frictional force acting on the block.
Homework Equations
Fgx = Fg sin theta
Fgy = Fg cos theta
Fg = mg
The Attempt at a Solution
Well I drew a diagram and solved for my Fgx component and my Fgy component:
Fgx = 40(9.8)sin35 = 224.8 N
Fgy = 40(9.8)cos35 = 321.1 N
Now what do I do? Take the sum of Fx ? Won't that just be 224.8 N ? That doesn't sound correct I'm confused. Am I doing something wrong?