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Fractions problem

tmt

Active member
Jan 15, 2014
236
I have this derivative and I need the slope at (1,3).

y' = [3(y-x)^2 -2x]/[3(y-x)^2]

With this equation I plug in x and y and the slope equals 5/6.

However, can't y' be simplified further to:

y' = [3(y-x)^2]/[3(y-x)^2] -2x/[3(y-x)^2] ?

Thus can't it be simplified to:

y'= -2x/[3(y-x)]^2

thus the slope would be -1/6 when I plug in x and y.


What am I doing wrong?

Thanks for all your help!
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Hint: \(\displaystyle \frac{a}{a}=1\) where \(\displaystyle a\ne0\)

You are trying to say \(\displaystyle \frac{a}{a}=0\).
 

Pindrought

New member
Mar 3, 2014
15
Hopefully this helps.

EDIT: Fixed Image

Get it now?