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- #1

y' = [3(y-x)^2 -2x]/[3(y-x)^2]

With this equation I plug in x and y and the slope equals 5/6.

However, can't y' be simplified further to:

y' = [3(y-x)^2]/[3(y-x)^2] -2x/[3(y-x)^2] ?

Thus can't it be simplified to:

y'= -2x/[3(y-x)]^2

thus the slope would be -1/6 when I plug in x and y.

What am I doing wrong?

Thanks for all your help!