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\(\displaystyle \sum_{n=0}^\infty \frac{1}{(2n-1)^2}=\frac{\pi^2}{8}\)

This question was set in an exam. I am in a position to try it if there is some interval say \(\displaystyle [-\pi \quad \pi]\) or like that.

But there is no interval in the question. Please give me some suggestion how to proceed.