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Perhaps you should draw a diagram of this. It doesn't make sense, the way you have stated it.Hydrous Caperilla said:If a diode is connected with P junction with higher voltage and N with low voltage then why is there a potential rise as opposed to the decrease in potential like in battery?
The direction of the current shown in your case (b) of forward bias is backwards. The current flows from p to n when forward biased. You can see this from the Diode Equation:Hydrous Caperilla said:@sophiecentaur edited
But it looks to me that the battery is connected the same way in both cases. The only difference is the battery volts. But his arrows seem to be showing the direction of electron flow, which is not helping.berkeman said:The direction of the current shown in your case (b) of forward bias is backwards.
Oh, that's confusing. He should show current direction, IMO.sophiecentaur said:his arrows seem to be showing the direction of electron flow, which is not helping.
A forward biased diode is a semiconductor device that allows current to flow in one direction when a voltage is applied across it. In this state, the diode has a low resistance and acts as a closed switch.
When a battery is connected in the forward direction to a diode, the positive terminal of the battery repels the holes in the P-type semiconductor, while the negative terminal attracts the electrons in the N-type semiconductor. This creates a potential difference across the diode, causing it to conduct current.
The potential rise of a forward biased diode is the increase in voltage across the diode when it is connected in the forward direction. This potential rise is typically around 0.7 volts for silicon diodes and 0.3 volts for germanium diodes.
The potential rise of a forward biased diode is important because it determines the minimum voltage required for the diode to start conducting. This voltage is known as the forward voltage and is an important parameter in the design of electronic circuits using diodes.
The battery affects the potential rise of a forward biased diode by providing the necessary voltage to overcome the potential barrier of the diode. The higher the battery voltage, the greater the potential rise across the diode, resulting in a higher current flow through the diode.