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please refer to the lower part , it states that [tex]|AB|= |AB| cos(\theta)[/tex]... after eliminate |vector b1 x vector b2|HallsofIvy said:
At the bottom of the third image you have |AC| = |AB|cos(##\theta##)gxc9800 said:
The formula for calculating the shortest distance between two skewed lines is given by d = |a1(x2-x1) + b1(y2-y1) + c1| / sqrt(a1^2 + b1^2), where (x1,y1) and (x2,y2) are any two points on the two lines and a1, b1, and c1 are the coefficients of the first line's equation in standard form.
The shortest distance between two skewed lines is important because it allows us to determine the closest possible distance between two non-parallel lines, which can be useful in various applications such as geometry, robotics, and computer graphics.
No, the shortest distance between two skewed lines cannot be negative. The shortest distance is always a positive value, as it represents the shortest length between the two lines.
The shortest distance between two skewed lines is different from the shortest distance between two parallel lines because parallel lines never intersect, so their shortest distance is always the same and can be calculated using simple geometry. On the other hand, two skewed lines may intersect at a single point or have no intersection at all, making the calculation of the shortest distance more complex.
Yes, there are many real-life applications of this formula. Some examples include calculating the shortest distance between two roads, determining the closest distance between two airplanes in flight, and finding the shortest distance between two lines of sight in surveying and navigation.
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