- #1
werson tan
- 183
- 1
Homework Statement
what is the 2.1 and 0.35 refers to in the equation of (9810)(2.1)(4.2)- 9810(0.35)(0.7) -Fx = 1000(5.88)(8.4-1.401) ??
is it the width ? but , the width is not given ?
haruspex said:Where the depth is 4.2m, the average depth is 2.1m, so the average pressure on the approach is 1000(9.81)(2.1)N/m2.
Multiplying by the height gives the force per unit width on the approach. Similarly on the exit side.
I do have one concern. The barrier is not 4.2m in height, so the calculated force on the approach side seems to much. To get a more accurate result we would need to find the height of the water surface above the highest point of the barrier.
ok , i can understand the red part of the equation (9810)(2.1)(4.2)- 9810(0.35)(0.7) -Fx = 1000(5.88)(8.4-1.401) , but 1000(5.88)(8.4-1.401) is force , am i right ? it's not force per unit width... they are not having the same unit...how cvan they be equqal to each other?haruspex said:Where the depth is 4.2m, the average depth is 2.1m, so the average pressure on the approach is 1000(9.81)(2.1)N/m2.
Multiplying by the height gives the force per unit width on the approach. Similarly on the exit side.
I do have one concern. The barrier is not 4.2m in height, so the calculated force on the approach side seems to much. To get a more accurate result we would need to find the height of the water surface above the highest point of the barrier.
do u mean since the width is unknown and constant through out the whole object , so we can take it out and leave the ans (Fx) is Force per unit width>haruspex said:Where the depth is 4.2m, the average depth is 2.1m, so the average pressure on the approach is 1000(9.81)(2.1)N/m2.
Multiplying by the height gives the force per unit width on the approach. Similarly on the exit side.
I do have one concern. The barrier is not 4.2m in height, so the calculated force on the approach side seems to much. To get a more accurate result we would need to find the height of the water surface above the highest point of the barrier.
Yes, we do not know the width, so all forces are considered per unit width.werson tan said:do u mean since the width is unknown and constant through out the whole object , so we can take it out and leave the ans (Fx) is Force per unit width>
The formula for calculating forces is F = m x a, where F represents force, m represents mass, and a represents acceleration.
The "2.1" in "Formula of Forces: 2.1 & 0.35 Meaning" refers to the coefficient of friction, which is a dimensionless quantity that measures the amount of friction between two surfaces.
The "0.35" in "Formula of Forces: 2.1 & 0.35 Meaning" refers to the coefficient of friction between two specific surfaces, which is used in the calculation of the force of friction between those surfaces.
Understanding the formula of forces is significant because it allows us to predict and calculate the effects of forces on objects, which is crucial in many scientific fields such as physics and engineering. It also helps us understand the relationship between mass, acceleration, and force.
The formula of forces can be applied in real-life situations such as calculating the force required to move an object, determining the forces acting on a moving car, or predicting the acceleration of a falling object. It is also used in designing structures and machinery to ensure their stability and safety.