Form Factor (Nuclear): Understanding F(q) & F(q^2)

[tigger88]

Homework Statement

I've been given a question using a spherically symmetric form of the form factor, but before I ask a specific question, I would like to get some more general advice and then try it on my own.
In my notes from lectures, the form factor is defined as:

F(q[tex]^{2}[/tex]) = 4[tex]\pi[/tex] [tex]\int[/tex]f(r) sin(|q|r/[tex]\hbar[/tex]) / (|q| r [tex]\hbar[/tex]) dr

But the question I've been given asks to find F(q). Is there some way to relate F(q) to F(q^2)?

Also, in the solution to this problem, my lecturer uses the following equation:

F(q) = 4(pi)/q [tex]\int[/tex][tex]\rho[/tex]r sin (qr) dr

What happened to the hbar and the r in the denominator?

Is there a website where I can learn about this in more detail, or even a textbook? I have been using Introductory Nuclear Physics by Krane and it doesn't seem to have much on it.

 

[NateD]

Homework EquationsF(q^{2}) = 4\pi \intf(r) sin(|q|r/\hbar) / (|q| r \hbar) drF(q) = 4(pi)/q \int\rhor sin (qr) drThe Attempt at a SolutionI'm not sure how to relate F(q) to F(q^2). I think it has something to do with the fact that q is a vector, so that the magnitude of q is q^2. But I'm not sure how to use that to solve the problem.Also, I'm not sure why my lecturer changed the equation from F(q^2) to F(q). It seems like the hbar and the r should still be in the denominator. I'm guessing that it has something to do with the fact that the magnitude of q is q^2, so the denominator can be simplified, but I'm not sure how.I would appreciate any advice or resources to help me understand this better. Thanks!