Forces acting on two stacked blocks

In summary, the problem involves finding the force required to accelerate a 1.5 kg block to the right at 2.5 m/s^2 while it is connected to a 7.5 kg block via a cord and a pulley with no friction. The only horizontal force acting on the top block is the tension, and for the bottom block to accelerate to the left at the same rate, the force applied must be greater than the tension.
  • #1
manaXmizery
3
0

Homework Statement


A 1.5 kg block rests on top of a 7.5 kg block which are attached using a cord to a pulley - there is no friction anywhere. What force must be applied to the bottom block so the top block accelerates to the right at 2.5 m/s^2?

Homework Equations


m1 = 1.5kg
a(to the right) = 2.5 m/s^2
m2 = 7.5kg

The Attempt at a Solution


Since we are interested in finding the horizontal force F , I neglected all the forces acting vertically on the two blocks mainly the normal Force , Fn and the weights of them . Am i right in assuming that :

1) there is no friction between the two blocks and as such , the only force acting horizontally on the top block is the tension Ft towards the right ?

2) for the bottom block , I have to assume that the force towards the left , F must be greater than the tension , Ft ?

Thanks in advance.

Regards,

Steve
Untitled.png
 
Physics news on Phys.org
  • #2
1) Correct.

2) If F was not larger than the tension, would m2 be accelerating?

Of course, an underlying assumption that you have not mentioned is that m2 will be accelerating to the left at 2.5 m/s^2 in order for the string length to be constant.
 

Related to Forces acting on two stacked blocks

What is the definition of forces acting on two stacked blocks?

Forces acting on two stacked blocks refers to the physical interactions between two blocks that are stacked on top of each other. These forces can be either external, such as gravity, or internal, such as friction between the two blocks.

How do you calculate the net force on two stacked blocks?

The net force on two stacked blocks is determined by adding up all the individual forces acting on the blocks. This includes both external and internal forces. If the net force is non-zero, the blocks will accelerate in the direction of the net force.

What is the relationship between the mass of the blocks and the forces acting on them?

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that the heavier the blocks, the more force is needed to accelerate them.

How do the forces between the two stacked blocks change if one of the blocks is removed?

If one of the blocks is removed, the forces acting on the remaining block will change. The weight of the removed block will no longer be acting on the remaining block, and the normal force between the two blocks will also be removed. This may result in a change in the net force and acceleration of the remaining block.

What other factors can affect the forces acting on two stacked blocks?

In addition to mass and gravity, other factors that can affect the forces acting on two stacked blocks include the surface material and texture of the blocks, the angle at which they are stacked, and the presence of external forces such as pushing or pulling. These factors can impact the friction and normal forces between the blocks and ultimately affect the net force and acceleration.

Similar threads

  • Introductory Physics Homework Help
Replies
13
Views
1K
  • Introductory Physics Homework Help
Replies
16
Views
1K
  • Introductory Physics Homework Help
Replies
15
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
17
Views
2K
  • Introductory Physics Homework Help
Replies
23
Views
2K
  • Introductory Physics Homework Help
Replies
20
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
5K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
1K
Back
Top