Force of Repulsion Between Charged Bodies: Calculating with Coulomb's Law

In summary, two similar charged bodies kept 5 cm apart in air will experience a force of repulsion governed by Coulomb's law. If the second body is shifted another 5 cm away from the first, the force of repulsion will decrease by 1/4 due to the inverse proportionality to the square of the distance between the bodies. This relationship holds true for any multiple of 5 cm.
  • #1
Deebu R
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Homework Statement


two similar charged bodies are kept 5 cm apart in air. If the second body is shifted away from the first another 5 cm, there force of repulsion will be?

Homework Equations


Coulomb's law? F= k (q1q2)/r^2?
 
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  • #2
What do you think? What are your thoughts on this problem? What does Coulomb's law govern?
 
  • #3
force of attraction or repulsion is directly proportional to product of charges and inversely proportional to square of the distance between them. So...if the r is moved by another 5 cm r^2 also increases.
When r= 5 r^2 = 25
When r=10 then r^2 is 100
Since it is inversely proportional the force reduces by 1/4. True?
 
  • #4
Deebu R said:
force of attraction or repulsion is directly proportional to product of charges and inversely proportional to square of the distance between them. So...if the r is moved by another 5 cm r^2 also increases.
When r= 5 r^2 = 25
When r=10 then r^2 is 100
Since it is inversely proportional the force reduces by 1/4. True?

Yep! When you double the distance, you reduce the force to 1/4 of its original strength. If you triple the distance, the force is reduced to 1/9 the strength.
 
  • #5
I was not sure if my answer was correct or not. Now I know. Thank you for your time.
 

Related to Force of Repulsion Between Charged Bodies: Calculating with Coulomb's Law

1. What is Coulomb's Law and how does it relate to the force of repulsion between charged bodies?

Coulomb's Law is a physical law that describes the force of repulsion between two charged objects. It states that the force of repulsion is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them. This means that the greater the charges and the smaller the distance between them, the stronger the repulsive force will be.

2. How can Coulomb's Law be used to calculate the force of repulsion between two charged bodies?

To calculate the force of repulsion between two charged bodies, you can use the equation F = k * (q1 * q2)/d^2, where F is the force of repulsion, k is the Coulomb's constant (9x10^9 N*m^2/C^2), q1 and q2 are the charges of the two bodies, and d is the distance between them.

3. Can Coulomb's Law be used for both like and unlike charges?

Yes, Coulomb's Law can be used for both like and unlike charges. The only difference is that for like charges (both positive or both negative), the force of repulsion will be positive, while for unlike charges (one positive and one negative), the force of repulsion will be negative, indicating an attractive force.

4. How does the distance between two charged bodies affect the force of repulsion?

The distance between two charged bodies has an inverse relationship with the force of repulsion. This means that as the distance between the two bodies increases, the force of repulsion decreases. This is because the farther apart the charges are, the weaker the electric field between them, resulting in a weaker force of repulsion.

5. What are some real-life applications of Coulomb's Law and the force of repulsion between charged bodies?

Coulomb's Law and the force of repulsion between charged bodies are used in many real-life applications, including electronic devices, such as computers and smartphones, which rely on the repulsion between charged particles to function. Additionally, it is used in the design of power lines, circuit breakers, and other electrical equipment. It is also important in understanding the behavior of atoms and molecules, as the interactions between charged particles play a crucial role in chemical reactions.

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