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Hereformore
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Homework Statement
A spring is compressed from both ends by 100 Newtons and the spring constant is given as 1000N/m. What is the net compression distance/displacement (x)?
Homework Equations
F=-k*change(x)
The Attempt at a Solution
Initially, I thought that the net displacement would be 20cm since i thought 100 Newtons applied at each end would lead to 10cm compression on each end. 100 = -(1000)*x so x = 10cm. 10cm compression on both sides leads to net compression of 20cm.
But I was wrong, and it's because of Newton's third law? So the force applied by one arm effectively serves as a wall so that compression can take place.
For some reason this seems counterintuitive for me. But i understand that if there were no other hand or wall there (so force applied to only one end), then the spring would simply accelerate to the right. So there needs to be a counter there (whether a wall or hand). If there was a wall, then it would return equal and opposite force to that applied by the spring, hence 100N. So the same principle would apply if there was a hand applying the same force instead.
What confuses me i guess is that we're talking a spring here so its not like we're pushing a block against a wall. I didnt expect the force that the spring would apply to a wall or the second hand to be the same as if the spring were substituted for a block. Would it be okay to see it as, the force applied when the spring is compressed to its maximum amount per that force?
Another reason why I am confused is because in another problem, it says that a spring is compressed from both sides by 5cm, and a force of 50N is applied by both sides. Yet here, we actually do consider the combined force to find the spring constant. How is it that here the spring compresses yet in the case i described above it doesnt?