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[tex]\left\{\begin{matrix} 3x-1 & x\leq 2\\ ax^{2}+bx+c & x>2 \end{matrix}\right.[/tex]

1. b=2-c

2. b=6+2c+2a

3. 7+c-2a

4. b=3-a-(3/4)c

I know that f(2)=5, and so is the limit of f when x goes to 2 from the left side.

I have calculated the limit when f goes to 2 from the right side, and I got:

4a+2b+c

and so for continuously I need:

4a+2b+c = 5

but here I got stuck...